A Regular Expression can be recursively defined as follows −
· ε is a Regular Expression indicates the language containing an empty string. (L (ε) = {ε})
· φ is a Regular Expression denoting an empty language. (L (φ) = { })
· x is a Regular Expression where L = {x}
· If X is a Regular Expression denoting the language L(X) and Y is a Regular Expression denoting the language L(Y), then
o X + Y is a Regular Expression corresponding to the language L(X) ∪ L(Y) where L(X+Y) = L(X) ∪ L(Y).
o X . Y is a Regular Expression corresponding to the language L(X) . L(Y) where L(X.Y) = L(X) . L(Y)
o R* is a Regular Expression corresponding to the language L(R*)where L(R*) = (L(R))*
· If we apply any of the rules several times from 1 to 5, they are Regular Expressions.
Some RE Examples
| Regular Expressions | Regular Set |
| (0 + 10*) | L = { 0, 1, 10, 100, 1000, 10000, … } |
| (0*10*) | L = {1, 01, 10, 010, 0010, …} |
| (0 + ε)(1 + ε) | L = {ε, 0, 1, 01} |
| (a+b)* | Set of strings of a’s and b’s of any length including the null string. So L = { ε, a, b, aa , ab , bb , ba, aaa…….} |
| (a+b)*abb | Set of strings of a’s and b’s ending with the string abb. So L = {abb, aabb, babb, aaabb, ababb, …………..} |
| (11)* | Set consisting of even number of 1’s including empty string, So L= {ε, 11, 1111, 111111, ……….} |
| (aa)*(bb)*b | Set of strings consisting of even number of a’s followed by odd number of b’s , so L = {b, aab, aabbb, aabbbbb, aaaab, aaaabbb, …………..} |
| (aa + ab + ba + bb)* | String of a’s and b’s of even length can be obtained by concatenating any combination of the strings aa, ab, ba and bb including null, so L = {aa, ab, ba, bb, aaab, aaba, …………..} |
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